(x+1)*(x^2-7x+12)=0

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Solution for (x+1)*(x^2-7x+12)=0 equation: 


Simplifying
(x + 1)(x2 + -7x + 12) = 0

Reorder the terms:
(1 + x)(x2 + -7x + 12) = 0

Reorder the terms:
(1 + x)(12 + -7x + x2) = 0

Multiply (1 + x) * (12 + -7x + x2)
(1(12 + -7x + x2) + x(12 + -7x + x2)) = 0
((12 * 1 + -7x * 1 + x2 * 1) + x(12 + -7x + x2)) = 0
((12 + -7x + 1x2) + x(12 + -7x + x2)) = 0
(12 + -7x + 1x2 + (12 * x + -7x * x + x2 * x)) = 0
(12 + -7x + 1x2 + (12x + -7x2 + x3)) = 0

Reorder the terms:
(12 + -7x + 12x + 1x2 + -7x2 + x3) = 0

Combine like terms: -7x + 12x = 5x
(12 + 5x + 1x2 + -7x2 + x3) = 0

Combine like terms: 1x2 + -7x2 = -6x2
(12 + 5x + -6x2 + x3) = 0

Solving
12 + 5x + -6x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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